Search Search Any Topic from Any Website Search
Bit Flipping and Equilibrium Theory In digital systems, we often want to bring a binary bit array to a specific equilibrium (e.g., all 1s or all 0s) using minimum operations . If we can flip exactly k bits at a time: Count the number of wrong bits: w . The minimum number of operations required = ceil(w / k) . If w % k ≠ 0 , the last operation may include already-correct bits. Flipping bits in a sliding window approach may require more steps, but choosing any k wrong bits at each step ensures the fewest operations. Example 1 Initial bits: [0, 1, 1, 0] Target equilibrium: all 1s → [1, 1, 1, 1] k = 2 (flip 2 bits at a time) Step 1: Count wrong bits Wrong bits = positions 0 and 3 → total w = 2 Minimum operations = ceil(w / k) = 1 Step 2: Flip 2 wrong bits Operation Bits Before Bits Flipped Bits After 1 [0, 1, 1, 0] [0, 3] [1, 1, 1, 1] Example 2: Sliding Window Bits: [0, 1, 0, 0, 1] Target: all 1s → [1, 1...