Skip to main content

Posts

Search

Search Search Any Topic from Any Website Search
Recent posts

The ideal long channel nMOSFET and pMOSFET devices shown in the circuits have threshold voltages of 1 V and −1 V ...

  The ideal long channel nMOSFET and pMOSFET devices shown in the circuits have threshold voltages of 1 V and −1 V, respectively. The MOSFET substrates are connected to their respective sources. Ignore leakage currents and assume that the capacitors are initially discharged. For the applied voltages as shown, the steady state voltages are _________________. Answer: for nMOSFET, Vgs ≥ Vth  Or, (Vg - Vs) ≥ Vth So, the maximum output voltage is limited to Vg - Vth or 5-1 = 4V For nMOSFET, Vgs  less than or equal to Vth  Or, (Vg - Vs) <= Vth If you were using a pMOS to pull an output down to ground (passing a "0"), it would be limited. It would turn off once the output reached: Vout,min =Vg + |Vth| or, 5V GATE EC Previous Year Papers with Solutions → Electronics and Communication Study Material →

Consider the 2-bit multiplexer (MUX) shown in the figure. For OUTPUT to be the XOR of C and D, the values for 𝐴0, 𝐴1, 𝐴2, and 𝐴3 are ____________.

Consider the 2-bit multiplexer (MUX) shown in the figure. For OUTPUT to be the XOR of C and D, the values for 𝐴0, 𝐴1, 𝐴2, and 𝐴3 are ____________. Answer: The Output will be  C D + C D   To select A0, C=0 & D=0 ; Output = 0 (=A0) To select A1, C=0 & D=1 ; Output = 1 (=A1) To select A2, C=1 & D=0 ; Output = 1 (=A2) To select A3, C=1 & D=1 ; Output = 0 (=A3) So, Correct Answer is Option (3) GATE EC Previous Year Papers with Solutions → Electronics and Communication Study Material →

Consider the CMOS circuit shown in the figure (substrates are connected to their respective sources)...

  Consider the CMOS circuit shown in the figure (substrates are connected to their respective sources). The gate width (𝑊) to gate length (𝐿) ratios W/L of the transistors are as shown. Both the transistors have the same gate oxide capacitance per unit area. For the pMOSFET, the threshold voltage is -1 V and the mobility of holes is 40 cm2 /V.s . For the nMOSFET, the threshold voltage is 1 V and the mobility of electrons is 300 cm2 /V.s . The steady state output voltage 𝑉0 is ________.  Answer: Mosfet current at saturation  μCox/2 * (W/L)*(Vgs - Vth)^2 Given: 300*1*(V0 - 1)^2 = 40*5*(4-V0-1)^2 Or, V0 = 1.898V So, Correct answer is Option C (less than 2V) GATE EC Previous Year Papers with Solutions → Electronics and Communication Study Material →

In a non-degenerate bulk semiconductor with electron density n = 10^16 cm^−3, the value of ...

Question In a non-degenerate bulk semiconductor with electron density n = 10 16 cm −3 , the value of (E C − E Fn ) = 200 meV , where E C and E Fn denote the bottom of the conduction band and electron Fermi level energy, respectively. Assume the thermal voltage as 26 meV and the intrinsic carrier concentration as 10 10 cm −3 . For n = 0.5 × 10 16 cm −3 , the closest approximation of the value of (E C − E Fn ) is: 226 meV 174 meV 218 meV 182 meV Step-by-Step Solution Step 1: Write the Carrier Concentration Equation For a non-degenerate semiconductor, the electron concentration is given by: n = n i exp[(E Fn − E i ) / kT] Alternatively, E C − E Fn = kT ln(N C / n) Since the effective density of states...

5G Beam Steering Simulation (Between BS & MS)

5G Bi-Directional Beamforming & SINR Lab 5G BEAM STEERING SYSTEM BS & MS Joint Steering + Interference Cancellation System SINR -- dB RX Power -- dBm 1. gNodeB (Base Station) Antennas ($N_{BS}$): 16 Large arrays at the tower create narrow "Pencil Beams" to maximize range. 2. UE (Mobile Station) Antennas ($N_{MS}$): 4 ...

Clarke-Jakes model Explained

  Understanding Clarke-Jakes Model: The Foundation of Rayleigh Fading A comprehensive guide to the Clarke-Jakes model, the Doppler Bathtub Spectrum, and precision Coherence Time calculations in wireless communications. What is Clarke’s Model? Clarke’s Model (often called the Clarke-Jakes model) is the mathematical framework used to describe small-scale fading in mobile wireless channels. It explains how a signal behaves when a receiver moves through a dense multipath environment where there is no direct Line-of-Sight (NLOS). Key Assumptions: A fixed transmitter and a moving receiver. An infinite number of scatterers (rich multipath). Signals arrive from all horizontal directions (360°) with equal probability. The received signal envelope follows a Rayle...

Is the -174 dBm/Hz Noise Floor Formula Universal?

  Is the -174 dBm/Hz Noise Floor Formula Universal? Understanding the limits of thermal noise calculations in RF engineering. In the world of RF engineering and wireless communication, the formula for calculating the noise floor is treated as gospel. For most terrestrial applications, we use the standard benchmark: P noise (dBm) = -174 + 10 * log 10 (Bandwidth) + NF While this equation is incredibly robust for designing cellular networks, Wi-Fi systems, and satellite links, it is not a universal law of physics applicable to every frequency. Depending on your environment and operating frequency, this formula can lead to significant errors. Where Does the "-174" Come From? The value -174 dBm/Hz is derived from the thermal noise power spectral density equation, P = kTB . Under standard conditions: k: Boltzmann’s Constant (1.38 × 10 -23 J/K). T: Absolute temperature, traditionally set at 290 K (Standard Room Temperature). When you convert this to dBm per 1 Hz of bandwidth...

RF Noise Floor Simulation

RF Noise Floor Simulation Master the formula: P noise = 10log 10 (kTB) + NF Noise Floor: -100 dBm System Parameters Bandwidth (B) in MHz 20 Noise Figure (NF) in dB 5 Temperature (T) in Kelvin 290 Wi-Fi (20MHz) LoRa (125kHz) LTE (10MHz) Cryo-SDR (10K) Calculated Noise Floor -100.0 dBm Calculation breakdown will appear here... Sensitivity Tip Total Noise Floor represents the poi...

Contact Us

Name

Email *

Message *