Q. The address of the first location of a 256 kilo byte (KB) memory is (2500)H. Choose the correct address of the last location of the memory. (A) (2FFF)H (B) (124FF)H (C) (424FF)H (D) (324FF)H The address of the first location of a 256 KB memory is (2500)H . Choose the correct address of the last location of the memory. Starting Address (2500)H Memory Size 256 KB Step-by-Step Solution Step 1: Convert Memory Size into Bytes We know that: \[ 1 KB = 1024 \text{ bytes} \] Given memory size = 256 KB. \[ 256 KB = 256 \...

  Let's derive the transfer function formula from the state-space equations step by step. Step 1: Start with the standard state-space equations The state equation is: x ˙ ( t ) = A x ( t ) + B u ( t ) \dot{x}(t)=Ax(t)+Bu(t) The output equation is: y ( t ) = C x ( t ) + D u ( t ) y(t)=Cx(t)+Du(t) Where: A A = System matrix B B = Input matrix C C = Output matrix D D = Feedforward matrix Step 2: Take the Laplace transform Taking the Laplace transform of: x ˙ ( t ) = A x ( t ) + B u ( t ) \dot{x}(t)=Ax(t)+Bu(t) We know that: L { x ˙ ( t ) } = s X ( s ) − x ( 0 ) \mathcal{L}\{\dot{x}(t)\}=sX(s)-x(0) Therefore, s X ( s ) − x ( 0 ) = A X ( s ) + B U ( s ) sX(s)-x(0)=AX(s)+BU(s) For zero initial conditions: x ( 0 ) = 0 x(0)=0 Hence, s X ( s ) = A X ( s ) + B U ( s ) sX(s)=AX(s)+BU(s) Step 3: Rearrange the equation Move A X ( s ) AX(s) to the left side: s X ( s ) − A X ( s ) = B U ( s ) sX(s)-AX(s)=BU(s) Taking X ( s ) X(s) commo...