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Binary Tree Explained


Binary Trees vs Arrays and Linked Lists

Different data structures organize data in different ways. Each one has strengths and weaknesses depending on whether you care more about fast access, fast insertion, or maintaining order.

1. Arrays

An array stores elements next to each other in memory.


Index:  0   1   2   3   4
Array: [10, 20, 30, 40, 50]

  

Strengths

  • Very fast direct access to elements

arr = [10, 20, 30, 40, 50]
print(arr[3])  # O(1) → 40

  

Weaknesses

  • Insertions and deletions are slow because elements must shift in memory

arr.insert(1, 15)
# [10, 15, 20, 30, 40, 50]

  

Time Complexity

Operation Time
Access O(1)
Insert / Delete (middle) O(n)

2. Linked Lists

A linked list is made of nodes, where each node points to the next.


10 → 20 → 30 → 40 → None

  

Strengths

  • Fast insertion and deletion (no shifting)

Weaknesses

  • Slow access since the list must be traversed

current = head
for _ in range(3):
    current = current.next

  

Time Complexity

Operation Time
Access O(n)
Insert / Delete O(1) (if node is known)

3. Binary Trees

A binary tree organizes data hierarchically. Each node has at most two children: left and right.


        30
       /  \
     20    40
    /  \
  10   25

  

Why Binary Trees Are Powerful

  • Faster access than linked lists
  • Faster insertion and deletion than arrays
  • No memory shifting required
  • Structured searching

Binary Search Trees (BST)

A Binary Search Tree follows this rule:

Left subtree < Node < Right subtree

        30
       /  \
     20    40
    /  \
  10   25

  

Python Node Structure


class Node:
    def __init__(self, value):
        self.value = value
        self.left = None
        self.right = None

  

Insert into a BST


def insert(root, value):
    if root is None:
        return Node(value)

    if value < root.value:
        root.left = insert(root.left, value)
    else:
        root.right = insert(root.right, value)

    return root

  

Searching in a BST


def search(root, target):
    if root is None:
        return False

    if root.value == target:
        return True
    elif target < root.value:
        return search(root.left, target)
    else:
        return search(root.right, target)

  

Searching skips half of the tree at each step, giving an average time of O(log n) when the tree is balanced.

Final Comparison

Structure Access Insert Delete Sorted Memory Shift
Array O(1) O(n) O(n) No Yes
Linked List O(n) O(1) O(1) No No
Binary Tree (BST / AVL) O(log n) O(log n) O(log n) Yes No

Summary

  • Arrays: Fast lookup, slow edits
  • Linked Lists: Easy edits, slow lookup
  • Binary Trees: Balanced performance

Further Reading


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