Overmodulation in AM and How It Causes Distortion
1. AM Signal Equation
s(t) = Ac [1 + μ m(t)] cos(2π fc t)
- Ac = carrier amplitude
- m(t) = normalized modulating signal (|m(t)| ≤ 1)
- μ = modulation index
2. Modulation Index
μ = Am / Ac
- Normal AM: 0 < μ ≤ 1 → no distortion
- Overmodulation: μ > 1 → distortion occurs
3. Envelope and Overmodulation
A(t) = Ac [1 + μ m(t)]
- For undistorted AM: 1 + μ m(t) ≥ 0 at all times
- If μ > 1: 1 + μ m(t) < 0 at negative peaks → carrier flips
Example:
Let m(t) = cos(2π fm t), Ac = 1 V, μ = 1.2
Minimum envelope: Amin = Ac [1 - 1.2] = -0.2 V
Negative amplitude → envelope crosses zero → 180° phase flip
4. Mathematical Consequence
-Ac cos(θ) = Ac cos(θ + π)
This phase reversal is what causes distortion in the demodulated signal.
5. Instantaneous AM Signal
s(t) = Ac [1 + μ cos(2π fm t)] cos(2π fc t)
- μ ≤ 1 → envelope detector works correctly
- μ > 1 → envelope < 0 at some t → distortion
6. Summary Equations
Envelope: A(t) = Ac (1 + μ m(t))
Overmodulation condition: μ |m(t)| > 1
Effect: A(t) < 0 → carrier flips phase → distortion
Summary
- Overmodulation occurs when μ > 1
- Negative envelope values flip carrier phase
- Envelope detector cannot follow negative peaks → distortion
- AM distortion is directly linked to the modulation index exceeding 1