In the given circuit, L = 1 μH and C = 1 μF. The phasor diagram for IC and IL is also shown. Assume the ...
Given Conditions
- L = 1 μH = 10⁻⁶ H
- C = 1 μF = 10⁻⁶ F
- Frequency = 159.15 kHz
- θ₁ = 45°
- θ₂ = 45°
Step 1: Calculate Angular Frequency
\[
\omega = 2\pi f
\]
\[
\omega = 2\pi \times 159.15 \times 10^3
\]
\[
\boxed{\omega \approx 10^6 \text{ rad/s}}
\]
Step 2: Calculate Inductive Reactance
\[
X_L = \omega L
\]
\[
X_L = 10^6 \times 10^{-6}
\]
\[
\boxed{X_L = 1\ \Omega}
\]
Step 3: Calculate Capacitive Reactance
\[
X_C = \frac{1}{\omega C}
\]
\[
X_C = \frac{1}{10^6 \times 10^{-6}}
\]
\[
\boxed{X_C = 1\ \Omega}
\]