In the following circuit β is in the range of 8 to 40. Rc = 11 Ω, Vcc = 200 V, Vb = 10 V. If the ...
Transistor Power Loss Given β min = 8 R C = 11 Ω V CC = 200 V V CE(sat) = 1 V V BE(sat) = 1.5 V Overdrive factor = 5 Collector Saturation Current I C = (V CC − V CE(sat) ) / R C I C = (200 − 1) / 11 = 18.09 A Forced Beta β f = 8 / 5 = 1.6 Therefore, the base current is: I B = I C / β f I B = 18.09 / 1.6 = 11.31 A Power Loss P = V CE(sat) I C + V BE(sat) I B P = (1)(18.09) + (1.5)(11.31) P ≈ 18.09 + 16.97 = 35.06 W Therefore, P ≈ 35.07 W . Answer: A (35.07 W) Browse All Solved Papers (2012 - 2025) → ...