FDM Bandwidth
Given
There are 10 channels, each having a bandwidth of 50 kHz.
Channel Bandwidth
10 × 50 = 500 kHz
There are 10 − 1 = 9 guard bands, with each guard band having a bandwidth of 1 kHz.
9 × 1 = 9 kHz
Hence, the total FDM bandwidth is:
BW = 500 + 9 = 509 kHz
Answer: C (509 kHz)
Further Reading:
GATE EC Previous Year Papers with Solutions