Skip to main content

Why do we require modulation in wireless communication?



Modulation : Why do we require modulation in wireless communication?



Wireless communication relies heavily on modulation techniques. Coaxial cable, twisted pair, and other types of wired communication are commonly used. Wired communication, on the other hand, is best for short-distance communication. An antenna is required for wireless communication to transfer signals. Now, if we want to send a baseband signal, we'll need a very large antenna with a range of many kilometers. Baseband signals are ones that typically contain a low or medium frequency message signal. It's also known as a message signal without modulation. Modulation is a technique for increasing the frequency of a message signal by the carrier frequency to a significantly higher frequency.
So, now I'll explain why modulation is necessary. The main two goals of modulation techniques are to reduce antenna height and to multiplex data (Multiplexing).


 Long-Distance Communication

Low-frequency base-band signals are not suitable for long-distance communication because they cannot generate a strong far field. The far field is the region where electromagnetic waves become plane waves and true wireless transmission occurs.

At low frequencies, the signal primarily creates a strong near field, which stores energy close to the antenna instead of radiating it efficiently into space. As a result, most of the energy remains near the source and does not propagate over long distances.

 

Reducing the height of antenna:

For short-range baseband communication, wired communication is sufficient. However, for long-distance communication, wireless is the best option. We know that the transmitter antenna emits a specific radiation pattern. The signal then travels through the earth's atmosphere until it reaches the receiver. We should be aware that antenna height is important for reliable transmission. The wavelength of the working frequency determines the antenna height. The antenna height should be

Ht = λ/4 and λ = c/f

Where, Ht = height of antenna

λ = wavelength of operating frequency

c = speed of light

f = operating frequency

We can also derive the following equations from the above equation:

As Ht = λ/4,

Therefore, Ht =c/4f; or Ht α 1/f

So, we can say that antenna’s height is inversely proportional to the operating frequency. If frequency is more, height of antenna should be smaller and vice-versa for reliable communication.

Example:

Let assume, operating frequency of a communication band is 20 KHz. Then the height of antenna, Ht, should be

Ht = c/4f = (3*10^8) / (4*20*10^3) = 3.75 kilometers

We can observe that the antenna height for reliable 20 KHz band communication should be 3.75 kilometers. As a result, we choose modulation, in which the lower frequency is shifted to the higher frequency. It is a method of enhancing transmission frequency while lowering antenna height.

On the other hand, if you use 100 MHz carrier signal then you only need a 0.75 meter antenna, which is perfectly practical for wireless communication (like FM radios, smartphones, etc.).


Multiplexing:

Multiplexing is another significant advantage of modulation techniques. The parallel data streams are multiplexed into a serial data stream. Simply put, modulation techniques allow us to deliver many simultaneous data streams from the transmitter to the receiver across a single channel. To your knowledge, we use the modulation technology to enable multiplexing in wired connection as well.

Noise Immunity and Signal Strength

Modulation schemes can be designed to make signals more resistant to noise, distortion, and interference.
For example, digital modulation techniques like QAM, PSK, or FSK improve bit error rate performance under noisy conditions.

Bandwidth Utilization

Modulation allows better utilization of available bandwidth, especially with advanced techniques like OFDM. It enables the transmission of high data rates in limited spectral resources.

Adaptability

Adaptive modulation helps wireless systems dynamically change their modulation scheme depending on channel conditions (e.g., switching from QPSK to 64-QAM in 4G/5G).

 

Further Reading

  1. Analog Modulation Techniques
  2. Digital Modulation Techniques  
  3. Importance of Modem in Telecommunication


Contact Us

Name

Email *

Message *

Popular Posts

UGC NET Electronic Science Previous Year Question Papers with Solutions

Home / Engineering & Other Exams / UGC NET 2026 PYQ ⬇️ Download Papers and Solutions 📋 Exam Pattern 💡 Preparation Tips ❓ FAQs 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2025 - Question Paper Download PDF June 2025 - Solved Paper + Explanation ...

UGC NET Electronic Science June 2025 Question Paper with Answer Key & Detailed Solutions

Home / UGC NET PYQ / June 2025 Solved UGC NET Electronic Science June 2025 Question Paper with Answer Key and Full Explanations 📥 Download Question Paper (PDF) 2025 2024 2023 2022 2021 2020 Explanations 1.  Answer: Option (3) For forming a p-type semiconductor, the dopant must be a trivalent impurity (three valence electrons) so that it creates acceptor levels and holes become the majority carriers. Among the given elements, boron (B) is a group-III element (trivalent). Arsenic (As) and phosphorus (P) are group-V (pentavalent) donors that produce n-type material, and germanium (Ge) is a group-IV element usually used as the semiconductor, not as an acceptor dopant. Hence, doping an intrinsic semiconductor with B produces a p-type semiconductor. 2.  Answer: Option (4) The ohmic resistance of a JFET at zero gate bias is given by the standard relation: R DS(on) = V P / I DSS ...

BER vs SNR for M-ary QAM, M-ary PSK, QPSK, BPSK, ...(MATLAB Code + Simulator)

Bit Error Rate (BER) & SNR Guide Analyze communication system performance with our interactive simulators and MATLAB tools. 📘 Theory 🧮 Simulators 💻 MATLAB Code 📚 Resources BER Definition SNR Formula BER Calculator MATLAB Comparison 📂 Explore M-ary QAM, PSK, and QPSK Topics ▼ 🧮 Constellation Simulator: M-ary QAM 🧮 Constellation Simulator: M-ary PSK 🧮 BER calculation for ASK, FSK, and PSK 🧮 Approaches to BER vs SNR What is Bit Error Rate (BER)? The BER indicates how many corrupted bits are received compared to the total number of bits sent. It is the primary figure of merit f...

Online Simulator for ASK, FSK, and PSK

Interactive Digital Signal Processing (DSP) Tutorial and Simulator for ASK, FSK, and BPSK modulation techniques. Try our new Digital Signal Processing Simulator!   •   Interactive ASK, FSK, and BPSK tools updated for 2025. Start Now Digital Modulation Visualizer: ASK, FSK, & BPSK Simulator Learn and visualize binary modulation techniques (ASK, FSK, BPSK) in real-time with adjustable carrier and sampling parameters. Perfect for DSP students and engineers. 📡 ASK Simulator 📶 FSK Simulator 🎚️ BPSK Simulator 📚 More Topics ASK Modulator FSK Modulator BPSK Modulator More Topics 1. ASK (Amplitude Shift Keying) Simulat...

UGC NET Electronic Science December 2024 Question Paper with Answer Key & Detailed Solutions

Home / UGC NET PYQ / June 2025 Solved UGC NET Electronic Science December 2024 Question Paper with Answer Key and Full Explanations 📥 Download Question Paper (PDF) 2025 2024 2023 2022 2021 2020 Q.1 Answer: Option (3) Q.2 Answer: Option (3) Solution 1. JMP SHORT LABEL Intrasegment (within the same code segment). Direct jump. ❌ Not intersegment indirect. 2. JMP 5000H:2000H Intersegment (far jump because both CS and IP are specified). Direct jump (address is explicitly given). ❌ Not indirect. 3. JMP [2000H] The destination address is taken from memory location 2000H. This is indirect. In 8086, a far indirect jump can use a memory operand containing both IP and CS (depending on operand size), making it an intersegment indirect jump. ✅ Correct answer. 4. JMP [BX] Indirect jump through memory addressed by BX. Usually intrasegment (near indirect jump). ❌ Not in...

Constellation Diagrams of ASK, PSK, and FSK (with MATLAB Code + Simulator)

Constellation Diagrams: ASK, FSK, and PSK Comprehensive guide to signal space representation, including interactive simulators and MATLAB implementations. 📘 Overview 🧮 Simulator ⚖️ Theory Q-function 📚 Resources 📂 Other Topics: M-ary PSK & QAM Diagrams ▼ 🧮 Simulator for M-ary PSK Constellation 🧮 Simulator for M-ary QAM Constellation BASK (Binary ASK) Modulation Transmits one of two signals: 0 or -√Eb, where Eb​ is the energy per bit. These signals represent binary 0 and 1. BFSK (Binary FSK) Modulation Transmits one of two signals: +√Eb​ (On the y-axis, the phas...

MATLAB Code for ASK, FSK, and PSK (with Online Simulator)

MATLAB Code for ASK, FSK, and PSK Comprehensive implementation of digital modulation and demodulation techniques with simulation results. 📘 Theory 📡 ASK Code 📶 FSK Code 🎚️ PSK Code 🕹️ Simulator 📚 Further Reading Amplitude Shift Frequency Shift Phase Shift Live Simulator ASK, FSK & PSK HomePage MATLAB Code MATLAB Code for ASK Modulation and Demodulation COPY % The code is written by SalimWireless.Com clc; clear all; close all; % Parameters Tb = 1; fc = 10; N_bits = 10; Fs = 100 * fc; Ts = 1/Fs; samples_per_bit = Fs * Tb; rng(10); binar...

Theoretical BER vs SNR for binary ASK, FSK, and PSK (with MATLAB Code + Simulator)

📘 Overview & Theory 🧮 MATLAB Codes 🧮 Q-function 📚 Further Reading Bit Error Rate (BER) Equations In ASK, noise directly affects the signal amplitude, making it the most vulnerable since the data is carried in amplitude changes. In FSK, data is represented by frequency variations, and because noise typically impacts amplitude more than frequency, FSK is more robust than ASK. In PSK, data is encoded in the signal phase, and BPSK specifically uses 180-degree phase shifts, creating the greatest separation between signal points and therefore achieving the lowest bit error rate (BER) for the same power level. BER formulas for ASK, FSK, and PSK modulation schemes. ASK BER = 0.5 × erfc(0.5 × √SNR) FSK BER = 0.5 × erfc(√(SNR / 2)) PSK BER = 0.5 × erfc(√SNR) ...