Impedance of a Series RLC Circuit
1. Series RLC Circuit Components
- R = Resistance (Ω)
- L = Inductance (H)
- C = Capacitance (F)
All components are in series, so the same current flows through each.
2. Impedance Definition
The total impedance Z is the opposition to AC current, combining resistance and reactance:
Z = R + j(XL - XC)
- j = √-1 (imaginary unit)
- XL = 2πfL (inductive reactance in Ω)
- XC = 1/(2πfC) (capacitive reactance in Ω)
- f = AC frequency in Hz
3. Magnitude of Impedance
|Z| = √(R² + (XL - XC)²)
4. Phase Angle
φ = tan⁻¹((XL - XC)/R)
φ > 0 → circuit is inductive
φ < 0 → circuit is capacitive
φ = 0 → resonance (XL = XC)
5. Step-by-Step Calculation Example
Given:
- R = 10 Ω
- L = 0.1 H
- C = 100 μF = 100 × 10⁻⁶ F
- f = 50 Hz
Step 1: Reactances
XL = 2Ï€fL ≈ 31.42 Ω
XC = 1/(2Ï€fC) ≈ 31.83 Ω
Step 2: Net Reactance
X = XL - XC = 31.42 - 31.83 = -0.41 Ω
Step 3: Impedance Magnitude
|Z| = √(R² + X²) = √(10² + (-0.41)²) ≈ 10.008 Ω
Step 4: Phase Angle
φ = tan⁻¹(X/R) = tan⁻¹(-0.41/10) ≈ -2.35°
Slightly capacitive because X < 0.
6. Summary Formulas
- Inductive Reactance:
XL = 2Ï€fL - Capacitive Reactance:
XC = 1/(2Ï€fC) - Impedance:
Z = R + j(XL - XC) - Magnitude:
|Z| = √(R² + (XL - XC)²) - Phase Angle:
φ = tan⁻¹((XL - XC)/R)