47.
The min terms for the following 'fmin' will be:
Answer: Option Cfmin = A'C' + A'D + A'B + BD
Solution
Finding Minterms for the Boolean Expression
Given Boolean expression:
Fmin = A'C' + A'D + A'B + BD
We determine all combinations of A, B, C, and D for which the function is equal to 1.
1. A'C'
Here A = 0 and C = 0, while B and D can be anything.
- 0000 = m0
- 0001 = m1
- 0100 = m4
- 0101 = m5
2. A'D
Here A = 0 and D = 1, while B and C vary.
- 0001 = m1
- 0011 = m3
- 0101 = m5
- 0111 = m7
3. A'B
Here A = 0 and B = 1, while C and D vary.
- 0100 = m4
- 0101 = m5
- 0110 = m6
- 0111 = m7
4. BD
Here B = 1 and D = 1, while A and C vary.
- 0101 = m5
- 0111 = m7
- 1101 = m13
- 1111 = m15
Final Minterm Form:
F(A,B,C,D) = Σm(0,1,3,4,5,6,7,13,15)