Determine VC and VB for the network given in the figure with β = 45, VBE = 0.7V.

50. Determine V_C and V_B for the network given in the figure with β = 45, V_BE = 0.7V.

1. 1. V_C = -4.48 V, V_B = -8.3 V
2. 2. V_C = -8.3 V, V_B = -4.48 V
3. 3. V_C = -3.52 V, V_B = -8.3 V
4. 4. V_C = -4.84 V, V_B = -4.77 V

Answer: 1

Solution

VE = VB - VBE

or, VB = VE + VBE = -9 + 0.7 = 8.3 V

Ic = 45*Ib

Ib = {0 - (-8.3)} / {100 *10^(-3)} = 83 micro-ohm

Ic = 45* 83 micro-ohm = 3.74 milli-ampere

Vc = 3.7 * 10^(-3) * 1.2 * 10^(3) = 4.48 V

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