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Self Bias, Source Bias, Voltage-divider Bias, and Current Divider Bias Explained

 

JFET Biasing Fundamentals

Let's find the fundamental concept you need is Kirchhoff's Voltage Law (KVL) applied to the Gate-Source input loop of the JFET.

In any JFET biasing circuit, the goal is to determine the relationship between the Drain current (ID) and the Gate-Source voltage (VGS). The general KVL equation for the input loop is:

VG − VGS − VS = 0
→ VGS = VG − VS

Here is how that fundamental logic applies to each specific biasing method:

1. Self-bias (A)
  • The Circuit: The gate is grounded through a resistor (VG = 0), and the source is connected to ground through a resistor RS.
  • The Math: Since VG = 0 and the voltage at the source VS = ID ⋅ RS, the equation becomes:
    VGS = 0 − ID ⋅ RS = −IDRS
2. Voltage-divider bias (B)
  • The Circuit: A resistive divider sets a constant voltage VG at the gate. The source is connected to ground through RS.
  • The Math: VGS = VG − ID ⋅ RS. If you rearrange this to solve for ID:
    ID ⋅ RS = VG − VGS
    → ID = (VG − VGS) / RS
3. Source bias (C)
  • The Circuit: This typically uses two power supplies (+VDD and −VSS). The gate is grounded (VG = 0), and the source resistor RS is connected to the negative supply −VSS.
  • The Math: The voltage drop across the source resistor is (VS − (−VSS)) = ID ⋅ RS, so VS = ID ⋅ RS − VSS.
    VGS = VG − VS = 0 − (ID ⋅ RS − VSS) = VSS − ID ⋅ RS
    Rearranging for ID:
    ID = (VSS − VGS) / RS
4. Current-source bias (D)
  • The Circuit: An active component, like a Bipolar Junction Transistor (BJT), is used to create a constant current source at the source lead of the JFET.
  • The Math: You can tell a formula belongs to a BJT if it contains VBE (base-emitter voltage) and RE (emitter resistor). The current provided by the BJT is approximately:
    ID ≈ IE = (VEE − VBE) / RE


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