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The Q of the coil using series connection measurement method is given by which of the following equations?


38) The Q of the coil using series connection measurement method is given by which of the following equations?
  1. \( Q_x = \frac{(C_1 - C_2)}{(C_1 Q_1 - C_2 Q_2)} \) [Option ID = 2981]
  2. \( Q_x = \frac{(C_1 - C_2)(Q_1 Q_2)}{(C_1 Q_1 - C_2 Q_2)} \) [Option ID = 2982]
  3. \( Q_x = \frac{(C_1 Q_1 - C_2 Q_2)}{(C_1 - C_2)} \) [Option ID = 2983]
  4. \( Q_x = \frac{C_1 Q_1 - C_2 Q_2}{(C_1 - C_2)(Q_1 Q_2)} \) [Option ID = 2984]
Correct Answer :
■ \( Q_x = \frac{(C_1 - C_2)(Q_1 Q_2)}{(C_1 Q_1 - C_2 Q_2)} \) [Option ID = 2982]
Answer: 2

Conceptual Solution for Question 38

Question 38 asks for the Quality Factor ($Q_x$) of a coil measured using the Series Substitution Method on a Q-Meter. Here is the fundamental breakdown:

1. The Fundamental Principle: Series Resonance

A Q-meter operates on the principle of series resonance. At the resonant frequency ($f$):

  • Inductive reactance ($X_L$) exactly cancels out Capacitive reactance ($X_C$).
  • The voltage across the capacitor is magnified by the Quality Factor: \( Q = \frac{X_L}{R} = \frac{1}{\omega C R} \).

2. Measurement Steps

Step 1: Initial Measurement (Without the unknown coil)

The circuit is tuned to resonance using only the internal work coil.

  • Resonance capacitance: \( C_1 \)
  • Measured Quality Factor: \( Q_1 \)
  • Circuit resistance is given by: \( R_1 = \frac{1}{\omega C_1 Q_1} \)
Step 2: Substitution Measurement (With the unknown coil)

The unknown coil is added in series, and the capacitor is retuned to find a new resonance.

  • New resonance capacitance: \( C_2 \)
  • New Quality Factor: \( Q_2 \)
  • Total resistance is now: \( R_{total} = R_1 + R_x = \frac{1}{\omega C_2 Q_2} \)
  • The unknown resistance is: \( R_x = \frac{1}{\omega C_2 Q_2} - \frac{1}{\omega C_1 Q_1} \)
  • The unknown reactance is: \( X_x = \frac{1}{\omega C_2} - \frac{1}{\omega C_1} \)

3. Deriving the Final Formula

The \( Q \) of the unknown coil is the ratio of its reactance to its resistance: \( Q_x = \frac{X_x}{R_x} \).

Substituting the values derived in Step 2:

\[ Q_x = \frac{\left( \frac{1}{\omega C_2} - \frac{1}{\omega C_1} \right)}{\left( \frac{1}{\omega C_2 Q_2} - \frac{1}{\omega C_1 Q_1} \right)} \]

By simplifying the common denominators and cancelling the \( \omega \) terms, we arrive at the final equation:

\[ Q_x = \frac{(C_1 - C_2) Q_1 Q_2}{C_1 Q_1 - C_2 Q_2} \]

Summary of Logic: The formula represents the ratio of the "Reactance Shift" to the "Resistance Shift" caused by adding the unknown component into the series resonant circuit.



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