Question 9
The Z-transform of e-t sampled at 10 Hz will be:
- z / (z - 10)
- z / (z - 0.1)
- z / (z - 0.9)
- z / (z - 1.1)
Options:
- Option 1 (ID = 12993)
- Option 2 (ID = 12994)
- Option 3 (ID = 12995)
- Option 4 (ID = 12996)
Solution:
z-transform of an equals to
1/{1 - a z(-1)} and |z| > |a|
So, z-transform of e(-t) equals to
1/{1 - e(-t) z(-1)} and |e(-t)| > |a|
Given z is sampled at 10 Hz, so t = 1/f = 1/10 = 0.1
Now, 1/{1 - e(-t) z(-1)} becomes
1/{1 - e(-0.1) z(-1)}
or, z/{z - e(-0.1)}
or, z/{z - 0.9} as e(-0.1) = 0.9
Further Reading:
GATE EC Previous Year Papers with Solutions