26. Vector A̅ = ŷ.3 + ẑ.2 and B̅ = x̂.5 + ŷ.8 extend from the origin. Find A̅.B̅
1. 15
2.16
3.24
4.6
Answer: C
solution
Dot product A̅.B̅ = |A̅||B̅|cos(theta)
and x̂.x̂ = 1, x̂.ŷ = x̂.ẑ = 0 and so on
So, A̅.B̅ = 24
26. Vector A̅ = ŷ.3 + ẑ.2 and B̅ = x̂.5 + ŷ.8 extend from the origin. Find A̅.B̅
1. 15
2.16
3.24
4.6
Answer: C
solution
Dot product A̅.B̅ = |A̅||B̅|cos(theta)
and x̂.x̂ = 1, x̂.ŷ = x̂.ẑ = 0 and so on
So, A̅.B̅ = 24