Induction Motor Torque
Given
- Frequency, f = 75 Hz
- Slip, s = 0.04
- Rotor resistance, R2 = 1 Ω
- Line voltage, VL = 415 V
Phase Voltage
Vph = 415 / √3 V
Since stator voltage drop and rotor reactance are neglected:
I2 =
Vph / (R2 / s)
Torque in Synchronous Watts
PT =
3Vph2 / (R2 / s)
PT =
3(415/√3)2
×
1/0.04
PT =
4152 / 0.04
≈ 6889 W
Thus,
T = 6889 synchronous watts
Answer: A (6889 synchronous watts)
Further Reading:
GATE EC Previous Year Papers with Solutions