Skip to main content

C++ Programming


How to run C++ program on your computer

To run any programming language on your local machine or computer you need a compiler first. The compiler reads each and every line of your program. It interprets line by line actually. If there is no error in the program, they only go ahead to run your particular program. In our case, we are using the "DEV C++" compiler to run our programs. You can easily download and install the "DEV C++ application file" or .exe file from the internet.


How to save C++ files on your computer

You simply go to your "DEV C++" and then click on "new" in the file section in the upper tabs. Then save the file adding the ".cpp" extension. For example, if your program name is "myfirstprogram" then save it as "myfirstprogram. cpp". 


Hello World program in C++

#include <iostream> 
using namespace std;           // it calls the library
int main() {                         // it defines the method main()
cout << "Hello World!";  // 'cout' is used for printing
return 0;                             // it returns only one value
}


Result

Hello World!


In the above program, "using namespace std;" calls a library that has a set of signs that are used to identify and refer to objects of various kinds. Here in the 3rd line main() is a method. 



How To Add Comments in C++ Programming

To add comments in C++ Programming you need to write "//", then write your comment. 

For Example

#include <iostream>

using namespace std;

int main() {

int x = 22; //declaring of variable x

if (x >= 10) {

cout << "It is true";

}

else {

cout << "It is false";

}

/* 

It is a comment on multiple lines

If...else is used for adding conditions in C programming

*/

return 0;

}


Here, in the above code single line comment is written after "//". But if comments contain multiple lines then we use "/* Your Comment of multiple lines */" as shown in the above code.



Declaring of Variable in C++

In all programming languages, we declare some variable for specific purposes.


#include <iostream>

using namespace std;

int main() {

  int x = 5;

  int y = 10;

  int sum = x + y;

  cout << "Value of x + y = " << sum;

}


Result

Value of x + y = 15


Here in the above code, we've declared two variables x = 5, and y=10.



'Else If' Condition in C++ Programming

#include <iostream>

using namespace std;

int main() {

  int product;

  cout << "Enter the number of product: ";

  cin >> product; 

  if (product < 500) {

    cout << "Total price = " << product*20;

  } else if (product >= 500 && product < 1000) {

    cout << "Total price = " << product*18;

  } else {

    cout << "Total price = " << product*15;

  }

  return 0;

}


Result

Enter the number of products: 400

Total price = 8000


We implemented three different conditions for an e-commerce application for the wholesale market in the code above. If you buy less than 500 items, you'll have to pay $20 for each one. If you buy more than 500 but fewer than 1000 units, you pay 18 dollars for each unit. The third condition is that if you purchase more than 1000 items, you will be charged $15 for each item.

 

While For - Loop in C++ Programming


We often need to run a loop inside a program to run several iterations and impose many logics, conditions, etc. 


Example

In a school sport, a group of three pupils will compete in a three-round running race. After each round, you must record the time taken by each student. Calculate the average time taken by each student over the three rounds once they have completed all of the rounds, and choose the student with the lowest average timing as the best runner. If more than one student meets the minimum average timing criteria, they must all be chosen. Show the fastest runner's name and average timing.


Solution in C++

Inputs:

The time taken by three students over three rounds to complete a 100-meter run is as follows

Student A: 8, 9, 9 (in second)

Student B: 9, 8, 12 (in second)

Student C: 7, 11, 9 (in second)

Condition:

All students will be judged unfit if they fail to maintain an average timing of 12 seconds over the three rounds, or if the time average taken by all students is greater than 12 seconds.

The input of the code is below:

8

9

7

9

8

11

9

12

9

Code:

#include <iostream>

#include <cmath>

using namespace std;

int main() {

int x, T1=0, T2=0, T3=0, count=1;

double A1, A2, A3;

while (count <=9)

{

cin >> x;

if(count%3==1)

T1=T1+x;

else if(count%3==2)

T2=T2+x;

else

T3=T3+x;

count++;

}

A1= (T1/3);

A2= (T2/3);

A3= (T3/3); 

if(A1>=12 && A2>=12 && A3>=12) {

cout<<"All trainees are unfit";

return 0;

}

if(A1<=A2 && A1<=A3){

cout<<"Student A"<<endl;

}

if(A2<=A1 && A2<=A3){

cout<<"Student B"<<endl;

}

if(A3<=A1 && A3<=A2){

cout<<"Student C"<<endl;

}

return 0;

}

Result:

Student A


We can say Student A takes less average time to cover 3 rounds of 100 meters runs.


 

Solve the following C Programs

#include<stdio.h>
int main() {
int a=2,b=2;
a=b<<a;
printf("%d", a);
return 0;
}


Output: 8


Explanation:

Operator "<<" denotes the left shifting of bits and operator ">>" denotes the right shifting of bits.

So, here operation occurs in bit level

b = 2 = binary 10; If we shift bits in the left direction by 2 places then it will be 1000 which is equal to decimal 8

So, the output will be 8 in the above code.



Contact Us

Name

Email *

Message *

Popular Posts

UGC NET Electronic Science Previous Year Question Papers with Solutions

Download Papers and Solutions Exam Pattern Preparation Tips FAQs More Home / Engineering & Other Exams / UGC NET 2026 PYQ 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2026 - Question Paper Download PDF June 202...

OFDM Symbols and Subcarriers Explained

This article explains how OFDM (Orthogonal Frequency Division Multiplexing) symbols and subcarriers work. It covers modulation, mapping symbols to subcarriers, subcarrier frequency spacing, IFFT synthesis, cyclic prefix, and transmission. Step 1: Modulation First, modulate the input bitstream. For example, with 16-QAM , each group of 4 bits maps to one QAM symbol. Suppose we generate a sequence of QAM symbols: s0, s1, s2, s3, s4, s5, …, s63 Step 2: Mapping Symbols to Subcarriers Assume N sub = 8 subcarriers. Each OFDM symbol in the frequency domain contains 8 QAM symbols (one per subcarrier): Mapping (example) OFDM symbol 1 → s0, s1, s2, s3, s4, s5, s6, s7 OFDM symbol 2 → s8, s9, s10, s11, s12, s13, s14, s15 … OFDM sym...

GMSK BER vs SNR (with Simulation)

  GMSK Performance: Why the BER vs. SNR Curve Matters If you’ve ever wondered why GMSK (Gaussian Minimum Shift Keying) became the backbone of the global GSM revolution, the answer lies in its unique balance of spectral efficiency and power performance. But there is no free lunch in engineering. To get that sleek, narrow spectrum, you have to pay a price in Bit Error Rate (BER) . In this guide, we break down the theoretical BER vs. SNR performance of GMSK, the "magic" of the BT product, and how to optimize your link budget for real-world conditions. What is GMSK and Why Should You Care? GMSK is a derivative of MSK (Minimum Shift Keying) that uses a Gaussian pre-modulation filter. This filter "smooths" the phase transitions, significantly reducing sideband power. The result? A constant envelope signal that allows you to use high-efficiency Class-C amplifiers without distorting the signal. This is the secr...

Flat vs Frequency Selective Online Simulator

Flat vs Frequency Selective Online Simulator Channel Type Without Fading Flat Fading Multipaths Nakagami m SNR(dB) Run Simulation Input Signal Signal After Fading Constellation Diagram BER vs SNR Explore Advanced Flat vs Frequency-Selective Fading Simulator Want to see these equations in action? Visualize it. Launch Simulator Tool Flat Fading and Frequency-Selective Fading Effects of Multipath Components and the Nakagami-m Parameter 1. Flat Fading Flat fading occurs when the signal bandwidth is smaller than the channel's coherence bandwidth, meaning that all frequency components of the transmitted signal experience approximately the same fading. It is typically associated with narrowband signals, where the multipath delay spread is small relative to the symbol duration. ...

MATLAB Code for ASK, FSK, and PSK (with Online Simulator)

MATLAB Code for ASK, FSK, and PSK Comprehensive implementation of digital modulation and demodulation techniques with simulation results. 📘 Theory 📡 ASK Code 📶 FSK Code 🎚️ PSK Code 🕹️ Simulator 📚 Further Reading Amplitude Shift Frequency Shift Phase Shift Live Simulator ASK, FSK & PSK HomePage MATLAB Code MATLAB Code for ASK Modulation and Demodulation COPY % The code is written by SalimWireless.Com clc; clear all; close all; % Parameters Tb = 1; fc = 10; N_bits = 10; Fs = 100 * fc; Ts = 1/Fs; samples_per_bit = Fs * Tb; rng(10); binar...

MATLAB Code for Constellation Diagram of QAM configurations such as 4, 8, 16, 32, 64, 128, and 256-QAM

📘 Overview of QAM 🧮 4-QAM MATLAB 🧮 16-QAM MATLAB 🚀 Online Simulator 📂 Other Topics on Constellation Diagrams... ▼ 🧮 MATLAB Code for 4-QAM 🧮 MATLAB Code for 16-QAM 🧮 MATLAB Code for m-ary QAM 🧮 Simulator for m-ary PSK 🧮 Simulator for m-ary QAM 🧮 Overview of Energy per Bit (Eb / N0) 🧮 Simulator for ASK, FSK, and PSK Overview of QAM One of the best-performing modulation techniques is QAM [↗] . Here, we modulate the symbols by varying the carrier signal's amplitude and phase in response to the variation in the message signal (or voltage variation). So, we may say that QAM is a combination of phase and amplitude modulation. Additionally, it performs better than ASK or PSK [↗] . In fact, any constellation for any type of modulatio...

UGC NET Electronic Science June 2026 Question Paper with Answer Key & Detailed Solutions

Home / UGC NET PYQ / June 2026 Solved UGC NET Electronic Science June 2026 Question Paper with Answer Key and Full Explanations 📥 Download Question Paper (PDF) 2025 2024 2023 2022 2021 2020 Explanations 1. Answer: Option (3) Total Students = 900 Urban Students = 7/10*400 + 4/5*500 = 680 680/900 * 100 = 75.56% 2. Answer: Option (1) Urban Students = 7/10*400 + 4/5*500 + 4/7*700 + 1/2 * 600 = 1380 3. Answer: Option (3) Male = 700*4/7 = 400 Female = 700*3/7=300 400-300=100 100/400*100 = 25% 4. Answer: Option (2) 400*3/10*40/100 + 500*1/5*60/100+700*3/7*50/100+600*1/3*30/100 = 318 5. Answer: Option (2) Total Female Students in B,C, and D colleges = 600 Female Post-graduates  = 100*60/100 + 300*50/100 + 200*30/100 = 270 270/600 *100 = 45% 6. Answer: Option (3) 7. Answer: Option (2) 8. Answer: Option (4) 9. Answer: Option (4) 10. Answer: Option (2) 11. Answer: Option (2) 12. Answer...