Skip to main content

Pulse Position Modulation (PPM)


Pulse Position Modulation (PPM) is a highly efficient signal modulation technique. Depending on the application, it is implemented using one of three primary methods: 1. Analog PPM (continuous shift), 2. Digital/M-ary PPM (discrete slots), and 3. Differential PPM (relative timing).

Digital Pulse Position Modulation (PPM) is a type of signal modulation in which M message bits are encoded by transmitting a single pulse within one of 2แดน possible time positions within a fixed time frame. This process is repeated every T seconds, resulting in a data rate of M/T bits per second.

Pulse Position Modulation Example (Analog Method)

PPM is a form of analog modulation where the position of each pulse is varied according to the amplitude of the sampled modulating signal, while the amplitude and width of the pulses remain constant. This means only the timing (position) of the pulse carries the information.

PPM is commonly used in optical and wireless communications, especially where multipath interference is minimal or needs to be reduced. Because the information is carried in timing, it's more robust in some noisy environments compared to other modulation schemes.

Although PPM can be used for analog signal modulation, it is also used in digital communications where each pulse position represents a symbol or bit pattern. However, it is not ideal for transmitting complex data files, as it is generally used for simple or low-data-rate signaling.

PPM waveform illustration
Fig: PPM Waveforms

Example: Pulse Position Modulation (PPM) of Sinusoidal Signal

We have a sinusoidal signal:

x(t) = A sin(2ฯ€ f t)

And we want to modulate this signal using Pulse Position Modulation (PPM).


Step-by-Step Example

1. Sinusoidal Signal

Let’s define a sinusoidal signal as:

x(t) = 5 sin(2ฯ€ ⋅ 1 ⋅ t)

This is a sine wave with:

  • Amplitude: A = 5
  • Frequency: f = 1 Hz

2. Pulse Position Modulation Concept

We’ll now encode information into the timing of pulses. To ensure robustness and avoid pulse overlapping, we use a small modulation index (k = 0.01).

If the amplitude is large, the pulse will be slightly delayed from its reference time. If it’s small, the pulse will stay closer to the reference time.

3. Calculating the Pulse Positions

We compute the values of x(t) and the corresponding pulse positions:

Time Sample 1: t = 0

x(0) = 5 sin(0) = 0

Pulse at reference time t = 0.

Time Sample 2: t = 0.1

x(0.1) = 5 sin(0.2ฯ€) ≈ 2.939
Shift = 0.01 × 2.939 = 0.0294
t = 0.1 + 0.0294 = 0.1294 seconds

Time Sample 3: t = 0.2

x(0.2) = 5 sin(0.4ฯ€) ≈ 4.7555
Shift = 0.01 × 4.7555 = 0.0475
t = 0.2 + 0.0475 = 0.2475 seconds

Time Sample 4: t = 0.3

x(0.3) = 5 sin(0.6ฯ€) ≈ 4.045
Shift = 0.01 × 4.045 = 0.0404
t = 0.3 + 0.0404 = 0.3404 seconds

Time Sample 5: t = 0.4

x(0.4) = 5 sin(0.8ฯ€) ≈ 2.939
Shift = 0.01 × 2.939 = 0.0294
t = 0.4 + 0.0294 = 0.4294 seconds

Time Sample 6: t = 0.5

x(0.5) = 5 sin(ฯ€) = 0
Pulse at reference time t = 0.5

4. Summary of Pulse Timing

Pulse positions based on sinusoidal amplitude (ensuring no overlap):

Sample Time (t) Amplitude x(t) Pulse Position (tpulse)
0.00.0000.0000
0.12.9390.1294
0.24.7550.2475
0.34.0450.3404
0.42.9390.4294
0.50.0000.5000

Demodulation of PPM Signal

Demodulation circuit for PPM

The noise-corrupted PPM waveform is received by the PPM demodulator circuit. A pulse generator produces fixed-duration pulses from the incoming signal and applies them to the reset (R) input of an SR flip-flop. Simultaneously, a synchronized reference pulse train (recovered via a Phase-Locked Loop) is applied to the set (S) input. The SR flip-flop generates a PWM waveform, which is then passed through a Low Pass Filter (LPF) to recover the original message.

Effect of Noise on Pulse Position Modulation

Since in a PPM system the transmitted information is contained in the relative positions of the modulated pulses, the presence of additive noise affects the performance by falsifying the perceived pulse timing. Immunity to noise can be improved by making the pulse rise rapidly, reducing the time window for noise interference.

In theory, noise would have no effect if pulses were perfectly rectangular (requiring infinite bandwidth). In practice, finite rise times mean some degradation is inevitable. Similar to continuous-wave modulation, PPM performance can be evaluated using the output signal-to-noise ratio (SNR). The figure of merit compares output SNR to channel SNR, showing that performance improves with bandwidth but suffers a threshold effect when SNR drops too low.


Try Interactive Online Simulation (web-based)

We have developed web-based interactive simulations to help you better understand Pulse Position Modulation and other complex concepts in wireless communication systems.

Try the Simulations:
PAM, PWM, & PPM Online Simulators


MATLAB Code for Analog Pulse Position Modulation

To get the MATLAB Code, click here 


Further Reading

  1. Pulse Amplitude Modulation (PAM)
  2. Pulse Width Modulation (PWM)
  3. Delta Modulation (DM)
  4. Pulse Code Modulation (PCM)
  5. Pulse Code Modulation in MATLAB
  6. PWM to PPM Conversion: Understanding Pulse Modulation Techniques


Contact Us

Name

Email *

Message *

Popular Posts

UGC NET Electronic Science Previous Year Question Papers with Solutions

Download Papers and Solutions Exam Pattern Preparation Tips FAQs More Home / Engineering & Other Exams / UGC NET 2026 PYQ ๐Ÿ“Š Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) ๐Ÿ“ฅ Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading ๐Ÿ“‚ View All Question Papers June 2026 - Question Paper Download PDF June 202...

GMSK BER vs SNR (with Simulation)

  GMSK Performance: Why the BER vs. SNR Curve Matters If you’ve ever wondered why GMSK (Gaussian Minimum Shift Keying) became the backbone of the global GSM revolution, the answer lies in its unique balance of spectral efficiency and power performance. But there is no free lunch in engineering. To get that sleek, narrow spectrum, you have to pay a price in Bit Error Rate (BER) . In this guide, we break down the theoretical BER vs. SNR performance of GMSK, the "magic" of the BT product, and how to optimize your link budget for real-world conditions. What is GMSK and Why Should You Care? GMSK is a derivative of MSK (Minimum Shift Keying) that uses a Gaussian pre-modulation filter. This filter "smooths" the phase transitions, significantly reducing sideband power. The result? A constant envelope signal that allows you to use high-efficiency Class-C amplifiers without distorting the signal. This is the secr...

The output voltage V0 (in Volt) for the network given in the Figure is ___

  Find the Output Voltage V o Solve the given circuit using Kirchhoff's Current Law (KCL), Ohm's law, and the supernode method. 1. Given Circuit Parameters Current source 1 mA Resistors 1 kฮฉ Each resistor Voltage source 6 V Required V o 2. Understand the Circuit The circuit contains a 1 mA current source, four 1 kฮฉ resistors, and a 6 V source connected between the two midpoint nodes. The output voltage is measured between the top and bottom rails. Reference node Take the bottom rail as ground: 0 V . Let the top rail voltage be V T , and...

What is a Supernode?

  Circuit Analysis What Is a Supernode? A supernode is formed when an ideal voltage source connects two non-reference nodes. It allows us to apply Kirchhoff's Current Law (KCL) to the combined circuit boundary. 1. Understanding a Supernode In nodal analysis, a voltage source between two unknown-voltage nodes makes the current through that source difficult to express directly using Ohm's law. We combine the two nodes and the voltage source into one extended region called a supernode. Key idea Apply KCL around the outer boundary of the supernode, then use the voltage source to write an additional voltage equation. 2. Supernode Circuit Diagram The voltage source connects nodes V L an...

A binary ripple counter is designed to count (0)₁₀ to (64)₁₀. Which of the following is/are the number of flip-flops required ...

  Q. A binary ripple counter is designed to count  (0)₁₀ to (64)₁₀ . Which of the following is/are the number of flip-flops required to design the counter?   (A) 6 (B) 7 (C) 4 (D) 5 Solution A binary ripple counter must count from (0)₁₀ to (64)₁₀ , including both endpoints. Step 1: Calculate the total number of states Since both 0 and 64 are included, add 1 to the difference: N = Last value − First value + 1 N = 64 − 0 + 1 = 65 states The counter visits every integer from 0 through 64: 0, 1, 2, 3, ..., 63, 64 There are 65 distinct states in total. Step 2: Calculate the number of flip-flops Each flip-flop stores one bit. With n flip-flops, the counter can represent 2โฟ distinct states. 2⁶ = 64 states (not enough) 2⁷ = 128 states (eno...

Parametric Down-Conversion of Photons

  Nonlinear Optics One incoming photon is converted into two lower-energy photons, typically in a nonlinear optical medium. Energy is conserved: E in = E 1 + E 2 E in ​ = E 1 ​ + E 2 ​ . Parametric Down-Conversion A nonlinear optical process in which one pump photon is converted into two lower-energy photons, known as the signal and idler photons. 1 Energy Conservation The energy of the pump photon equals the sum of the energies of the signal and idler photons. \[ \boxed{\hbar\omega_p=\hbar\omega_s+\hbar\omega_i} \] \[ \boxed{\omega_p=\omega_s+\omega_i} \] ฯ‰โ‚š Pump angular frequency ...

SRAM, DRAM, EPROM, MRAM, and DDRAM Explained

Computer Fundamentals Types of Memory and Their Technologies Understand the fundamental relationship between different types of computer memory and the technologies used to implement them. Fundamental Matching Memory type, technology, and key characteristics Memory Type Technology Key Characteristic Cache Memory SRAM Very fast; stores frequently accessed data Main Memory DRAM Holds programs and data currently in use Au...

The cutoff frequency (in GHz) for the dominant TE10 mode of an air-filled rectangular waveguide of ...

  Q. The cutoff frequency (in GHz) for the dominant TE10 mode of an air-filled rectangular waveguide of inner dimension 0.28 inch×0.14 inch is __. (rounded off to two decimal places). Given Information Waveguide dimensions = 0.28 inch × 0.14 inch Wider dimension (a) = 0.28 inch Smaller dimension (b) = 0.14 inch Medium = Air Dominant mode = TE 10 Speed of light (c) = 3 × 10 8 m/s Step 1: Cutoff Frequency Formula The cutoff frequency of a rectangular waveguide is: f c = (c / 2) √[(m/a) 2 + (n/b) 2 ] For the dominant TE 10 mode: m = 1, n = 0 f c = c / 2a Step 2: Convert Inch into Meter We know that 1 inch = 0.0254 meter. a = 0.28 × 0.0254 a = 0.007112 m ...