Skip to main content

Pulse Position Modulation (PPM)


Pulse Position Modulation (PPM) is a highly efficient signal modulation technique. Depending on the application, it is implemented using one of three primary methods: 1. Analog PPM (continuous shift), 2. Digital/M-ary PPM (discrete slots), and 3. Differential PPM (relative timing).

Digital Pulse Position Modulation (PPM) is a type of signal modulation in which M message bits are encoded by transmitting a single pulse within one of 2á´¹ possible time positions within a fixed time frame. This process is repeated every T seconds, resulting in a data rate of M/T bits per second.

Pulse Position Modulation Example (Analog Method)

PPM is a form of analog modulation where the position of each pulse is varied according to the amplitude of the sampled modulating signal, while the amplitude and width of the pulses remain constant. This means only the timing (position) of the pulse carries the information.

PPM is commonly used in optical and wireless communications, especially where multipath interference is minimal or needs to be reduced. Because the information is carried in timing, it's more robust in some noisy environments compared to other modulation schemes.

Although PPM can be used for analog signal modulation, it is also used in digital communications where each pulse position represents a symbol or bit pattern. However, it is not ideal for transmitting complex data files, as it is generally used for simple or low-data-rate signaling.

PPM waveform illustration
Fig: PPM Waveforms

Example: Pulse Position Modulation (PPM) of Sinusoidal Signal

We have a sinusoidal signal:

x(t) = A sin(2Ï€ f t)

And we want to modulate this signal using Pulse Position Modulation (PPM).


Step-by-Step Example

1. Sinusoidal Signal

Let’s define a sinusoidal signal as:

x(t) = 5 sin(2Ï€ ⋅ 1 ⋅ t)

This is a sine wave with:

  • Amplitude: A = 5
  • Frequency: f = 1 Hz

2. Pulse Position Modulation Concept

We’ll now encode information into the timing of pulses. To ensure robustness and avoid pulse overlapping, we use a small modulation index (k = 0.01).

If the amplitude is large, the pulse will be slightly delayed from its reference time. If it’s small, the pulse will stay closer to the reference time.

3. Calculating the Pulse Positions

We compute the values of x(t) and the corresponding pulse positions:

Time Sample 1: t = 0

x(0) = 5 sin(0) = 0

Pulse at reference time t = 0.

Time Sample 2: t = 0.1

x(0.1) = 5 sin(0.2Ï€) ≈ 2.939
Shift = 0.01 × 2.939 = 0.0294
t = 0.1 + 0.0294 = 0.1294 seconds

Time Sample 3: t = 0.2

x(0.2) = 5 sin(0.4Ï€) ≈ 4.7555
Shift = 0.01 × 4.7555 = 0.0475
t = 0.2 + 0.0475 = 0.2475 seconds

Time Sample 4: t = 0.3

x(0.3) = 5 sin(0.6Ï€) ≈ 4.045
Shift = 0.01 × 4.045 = 0.0404
t = 0.3 + 0.0404 = 0.3404 seconds

Time Sample 5: t = 0.4

x(0.4) = 5 sin(0.8Ï€) ≈ 2.939
Shift = 0.01 × 2.939 = 0.0294
t = 0.4 + 0.0294 = 0.4294 seconds

Time Sample 6: t = 0.5

x(0.5) = 5 sin(Ï€) = 0
Pulse at reference time t = 0.5

4. Summary of Pulse Timing

Pulse positions based on sinusoidal amplitude (ensuring no overlap):

Sample Time (t) Amplitude x(t) Pulse Position (tpulse)
0.00.0000.0000
0.12.9390.1294
0.24.7550.2475
0.34.0450.3404
0.42.9390.4294
0.50.0000.5000

Demodulation of PPM Signal

Demodulation circuit for PPM

The noise-corrupted PPM waveform is received by the PPM demodulator circuit. A pulse generator produces fixed-duration pulses from the incoming signal and applies them to the reset (R) input of an SR flip-flop. Simultaneously, a synchronized reference pulse train (recovered via a Phase-Locked Loop) is applied to the set (S) input. The SR flip-flop generates a PWM waveform, which is then passed through a Low Pass Filter (LPF) to recover the original message.

Effect of Noise on Pulse Position Modulation

Since in a PPM system the transmitted information is contained in the relative positions of the modulated pulses, the presence of additive noise affects the performance by falsifying the perceived pulse timing. Immunity to noise can be improved by making the pulse rise rapidly, reducing the time window for noise interference.

In theory, noise would have no effect if pulses were perfectly rectangular (requiring infinite bandwidth). In practice, finite rise times mean some degradation is inevitable. Similar to continuous-wave modulation, PPM performance can be evaluated using the output signal-to-noise ratio (SNR). The figure of merit compares output SNR to channel SNR, showing that performance improves with bandwidth but suffers a threshold effect when SNR drops too low.


Try Interactive Online Simulation (web-based)

We have developed web-based interactive simulations to help you better understand Pulse Position Modulation and other complex concepts in wireless communication systems.

Try the Simulations:
PAM, PWM, & PPM Online Simulators


MATLAB Code for Analog Pulse Position Modulation

To get the MATLAB Code, click here 


Further Reading

  1. Pulse Amplitude Modulation (PAM)
  2. Pulse Width Modulation (PWM)
  3. Delta Modulation (DM)
  4. Pulse Code Modulation (PCM)
  5. Pulse Code Modulation in MATLAB
  6. PWM to PPM Conversion: Understanding Pulse Modulation Techniques


Contact Us

Name

Email *

Message *

Popular Posts

CMOS Logic Gates: Inverter, NAND, and NOR

CMOS Logic Gates: Inverter, NAND, and NOR Complementary metal–oxide–semiconductor (CMOS) technology forms the backbone of modern digital IC design. Patented by Frank Wanlass in 1963 ( US patent 3,356,858 ), CMOS enables low-power, high-speed, and noise-immune logic circuits. CMOS gates, including inverters, NAND, and NOR, are widely used in both large-scale and small-scale integrated circuits due to their efficiency and versatility. CMOS Inverter A CMOS inverter consists of a complementary pair of PMOS and NMOS transistors. The PMOS transistor connects to the supply voltage V DD , while the NMOS connects to ground. The input voltage V IN controls both gates, and the output voltage V OUT is taken from the connected drains. CMOS inverters are highly energy-efficient and produce minimal heat due to their comple...

UGC NET Electronic Science Previous Year Question Papers with Solutions

Download Papers and Solutions Exam Pattern Preparation Tips FAQs More Home / Engineering & Other Exams / UGC NET 2026 PYQ 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2026 - Question Paper Download PDF June 202...

OFDM Symbols and Subcarriers Explained

This article explains how OFDM (Orthogonal Frequency Division Multiplexing) symbols and subcarriers work. It covers modulation, mapping symbols to subcarriers, subcarrier frequency spacing, IFFT synthesis, cyclic prefix, and transmission. Step 1: Modulation First, modulate the input bitstream. For example, with 16-QAM , each group of 4 bits maps to one QAM symbol. Suppose we generate a sequence of QAM symbols: s0, s1, s2, s3, s4, s5, …, s63 Step 2: Mapping Symbols to Subcarriers Assume N sub = 8 subcarriers. Each OFDM symbol in the frequency domain contains 8 QAM symbols (one per subcarrier): Mapping (example) OFDM symbol 1 → s0, s1, s2, s3, s4, s5, s6, s7 OFDM symbol 2 → s8, s9, s10, s11, s12, s13, s14, s15 … OFDM sym...

IIR Filter Simulation

IIR Filter & Feedback Lab IIR Filter & Feedback Lab Exploring Recursive Systems: Where Output depends on Output 1 Input Signal $x[n]$ Signal Type Unit Impulse δ[n] Sine Wave Unit Step u[n] Frequency (for Sine) Notice: With an Impulse input, the output of an IIR filter can ring forever (Infinite response). 2 Feedback Coefficients Numerator $b$ (Feed-forward) Denominator $a$ (Feedback - $a_0$ is always 1) System Stable Try setting $a$ to 1.0, -1.1 to see an unstable system! ...

Online Simulator for Frequency Modulatiuon and Demodulation

FM Modulation Simulator Frequency Modulation (FM) In Frequency Modulation, the frequency of the carrier signal varies in accordance with the message signal's amplitude. s FM (t) = A c cos(ω c t + k f ∫m(t)dt) where ω = 2Ï€f & k f = Frequency Sensitivity Modulation index, β = (k f * A m ) / f m Change the parameter values to see the effect. Message Freq (Hz) 1 Carrier Freq (Hz) Message Amplitude (Am) Kf (sensitivity): 50 Perform FM Demodulation 🧪 Experiment for Students: ...

(Filters) Free MATLAB alternative for signal analysis

Advanced Signal Filters Upload CSV (1st Col) or Audio (WAV, MP3, etc.) Generate Messy Signal (20Hz + 50Hz + 150Hz) No Operation FFT (Spectrum) Amplitude Modulation (AM) Double Sideband Supressed Carrier (DSBSC) Pulse Amplitude Modulation (PAM) Flat Top PAM Filters - LPF, HPF, BPF, Notch Principal Component Analysis (PCA) Cross Spectrum Filter Type: Signal Cleaner ...

The electric field of a monochromatic plane wave travelling in a lossless isotropic and homogenous medium is given by E(z, t) = ...

  Q. The electric field of a monochromatic plane wave travelling in a lossless isotropic and homogenous medium is given by E(z, t) = E₀ [x̂ cos(ωt − kz) + Å· sin(ωt − kz)] in a right-handed orthogonal co-ordinate system. Which of the following is the correct polarization of the electromagnetic wave? (A) Right-handed circularly polarized Correct answer under the IEEE convention. (B) Left-handed circularly polarized (C) Linearly polarized (D) Linearly polarized at −45° to x̂ Solution 1. Identify the electric-field components Let ψ = ωt − kz. The components along the x and y directions are: Eâ‚“ = E₀ cos ψ Eáµ§ = E₀ sin ψ Both components have equal amplitudes, the same frequency, and a phase difference of 90°. These are the conditions for circular polarization. ...

3rd and 4th Order Filters Simulation

High-Order System Simulator System Configuration 3RD ORDER 4TH ORDER STAGE 1 (2nd Order Section) Damping (ζ₁) 0.707 Frequency (ωn₁) 1000 STAGE 2 (2nd Order Section) Damping (ζ₂) 0.707 Frequency (ωn₂) 1000 -80 dB/DECADE Higher Order Control Theory A 4th Order System is the result of multiplying two 2nd-order transfer functions: H(s) = H₁(s) × H₂(s) . In the frequency domain, this means their magnitudes add (in dB) and their phases add . ...