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The transmitted signal in a GSM system is of 200 kHz bandwidth, and 8 users ...

 

The transmitted signal in a GSM system is of 200 kHz bandwidth, and 8 users share a common bandwidth using TDMA.
If at a given time 12 users are talking in a cell, the total bandwidth of the signal received by the base station of the cell will be at least (in kHz).



Solution: GSM Bandwidth with TDMA

In a GSM system, one carrier channel has a bandwidth of 200 kHz and supports 8 users using TDMA.

Bandwidth per user:

Bandwidth per user = 200 kHz / 8 = 25 kHz

Given that 12 users are talking simultaneously, the number of required carrier channels is:

Number of carriers = 12 / 8 = 1.5

Since partial carriers are not possible, we need 2 full carriers.

Total bandwidth received at the base station:

Total Bandwidth = 2 × 200 kHz = 400 kHz

Final Answer: 400 kHz

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