Question:
For the given circuit, determine the Thevenin equivalent circuit at terminals a–b.
(Insert circuit diagram image here if needed)
Solution:
Step 1: Find Open-Circuit Voltage (Vth)
With terminal a open, no current flows through the 10ฮฉ resistor, so Va = Vn.
Applying KCL at node n:
(Vn - 6)/8 - Vn/4 = 0
Solving:
(Vn - 6)/8 = Vn/4
Vn - 6 = 2Vn
Vn = -6 V
Therefore:
Vth = -6 V
Step 2: Find Thevenin Resistance (Rth)
Turn off the 6V source (replace with short circuit). Apply a test voltage Vt at terminal a.
KCL at node n:
Vn/8 + (Vn - Va)/10 - Va/4 = 0
Solving:
5Vn + 4(Vn - Va) - 10Va = 0
9Vn = 14Va
Vn = (14/9)Va
Test current:
It = (Va - Vn)/10
It = (Va - 14/9 Va)/10
It = -Va/18
Therefore:
Rth = -18 ฮฉ
Final Answer:
Thevenin Equivalent: Vth = -6 V, Rth = -18 ฮฉ
