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Consider the two-dimensional vector field ๐น⃗(๐‘ฅ,๐‘ฆ)=๐‘ฅ ๐šค⃗+๐‘ฆ ๐šฅ⃗, where ๐šค⃗ and ๐šฅ⃗ denote the unit vectors along the ๐‘ฅ-axis and the ๐‘ฆ-axis, respectively.


Question

Consider the two-dimensional vector field

F(x, y) = x i + y j,

where i and j denote the unit vectors along the x-axis and y-axis respectively. The contour C in the x-y plane is composed of two horizontal line segments connected at the two ends by semicircular arcs of unit radius. The contour is traversed in the counter-clockwise direction. Evaluate

C F(x,y) · (dx i + dy j)

Contour (Approximate)

x y (0,0) (0,2) (4,0)

Solution

The given vector field is

F(x,y) = x i + y j.

The required line integral is

C (x dx + y dy).

Observe that

x dx + y dy = d((x² + y²)/2).

Hence the vector field is conservative with potential function

ฯ†(x,y) = (x² + y²)/2.

For any conservative vector field, the line integral over a closed curve is equal to the change in the potential between the initial and final points. Since a closed curve starts and ends at the same point,

C F · dr = ฯ†(final) − ฯ†(initial) = 0.

Alternative Verification (Green's Theorem)

Let

P = x,    Q = y.

Green's theorem gives

C (P dx + Q dy) = ∬R (∂Q/∂x − ∂P/∂y) dA.

Since

∂Q/∂x = 0,    ∂P/∂y = 0,

we obtain

C (x dx + y dy) = ∬R 0 dA = 0.

Final Answer: 0

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