Skip to main content

Spectral Efficiency Simulation for various Modulation Schemes


Spectral Efficiency Lab

Determine if your channel bandwidth supports your chosen modulation scheme.

Default: Null-to-Null BW ($B = 2R_s$)

Current Efficiency (η): 0.5 b/s/Hz

Required Bandwidth for this setup:

20.00 kHz

Signal Processing Knowledge Check

Which modulation technique is most susceptible to power-line noise and fading?

Efficiency vs. Resilience

Higher spectral efficiency (like 64-QAM) allows you to pack more data into the same bandwidth, but it requires a much cleaner signal (High SNR) to avoid errors.

The BW Trade-off

For BPSK, the Null-to-Null bandwidth is $2R_b$. If you use pulse-shaping (like Raised Cosine), you can approach the Nyquist limit of $1R_b$.

Why BPSK Wins

Even though BPSK has low spectral efficiency (0.5 to 1.0), its 3dB advantage over BFSK makes it the standard for Deep Space Telemetry.

M-ary Logic

In QPSK ($M=4$), each symbol carries 2 bits. This doubles the efficiency compared to BPSK without increasing the bandwidth.

Ready for the BER vs SNR analysis?

Visualize how noise power affects these efficiency levels.

Launch Simulator

Contact Us

Name

Email *

Message *

Popular Posts

UGC NET Electronic Science Previous Year Question Papers with Solutions

Home / Engineering & Other Exams / UGC NET 2026 PYQ ⬇️ Download Papers and Solutions 📋 Exam Pattern 💡 Preparation Tips ❓ FAQs 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2025 - Question Paper Download PDF June 2025 - Solved Paper + Explanation ...

UGC NET Electronic Science June 2025 Question Paper with Answer Key & Detailed Solutions

Home / UGC NET PYQ / June 2025 Solved UGC NET Electronic Science June 2025 Question Paper with Answer Key and Full Explanations 📥 Download Question Paper (PDF) 2025 2024 2023 2022 2021 2020 Explanations 1.  Answer: Option (3) For forming a p-type semiconductor, the dopant must be a trivalent impurity (three valence electrons) so that it creates acceptor levels and holes become the majority carriers. Among the given elements, boron (B) is a group-III element (trivalent). Arsenic (As) and phosphorus (P) are group-V (pentavalent) donors that produce n-type material, and germanium (Ge) is a group-IV element usually used as the semiconductor, not as an acceptor dopant. Hence, doping an intrinsic semiconductor with B produces a p-type semiconductor. 2.  Answer: Option (4) The ohmic resistance of a JFET at zero gate bias is given by the standard relation: R DS(on) = V P / I DSS ...

BER vs SNR for M-ary QAM, M-ary PSK, QPSK, BPSK, ...(MATLAB Code + Simulator)

Bit Error Rate (BER) & SNR Guide Analyze communication system performance with our interactive simulators and MATLAB tools. 📘 Theory 🧮 Simulators 💻 MATLAB Code 📚 Resources BER Definition SNR Formula BER Calculator MATLAB Comparison 📂 Explore M-ary QAM, PSK, and QPSK Topics ▼ 🧮 Constellation Simulator: M-ary QAM 🧮 Constellation Simulator: M-ary PSK 🧮 BER calculation for ASK, FSK, and PSK 🧮 Approaches to BER vs SNR What is Bit Error Rate (BER)? The BER indicates how many corrupted bits are received compared to the total number of bits sent. It is the primary figure of merit f...

Q-function in BER vs SNR Calculation

Q-function in BER vs. SNR Calculation | Interactive Guide Q-function in BER vs. SNR Calculation In digital communications and signal processing, the Q-function plays a significant role in predicting system reliability. It allows engineers to quantify the probability that Gaussian noise will exceed a specific threshold, causing a bit error. What is the Q-function? The Q-function is a mathematical function representing the tail probability of the standard normal (Gaussian) distribution. It is the complementary cumulative distribution function (CCDF) of a standard Gaussian distribution. Q(x) = (1 / √(2Ï€)) ∫â‚“∞ e^(-t² / 2) dt Q-Function Interactive Simulator Move the slider to see how the "Tail Probability" (the area in red) changes. This area represents the Probability of Error (BER) . Threshold Distance ( x ) — (Simulates Increasing SNR) ...

UGC NET Electronic Science December 2024 Question Paper with Answer Key & Detailed Solutions

Home / UGC NET PYQ / June 2025 Solved UGC NET Electronic Science December 2024 Question Paper with Answer Key and Full Explanations 📥 Download Question Paper (PDF) 2025 2024 2023 2022 2021 2020 Q.1 Answer: Option (3) Q.2 Answer: Option (3) Solution 1. JMP SHORT LABEL Intrasegment (within the same code segment). Direct jump. ❌ Not intersegment indirect. 2. JMP 5000H:2000H Intersegment (far jump because both CS and IP are specified). Direct jump (address is explicitly given). ❌ Not indirect. 3. JMP [2000H] The destination address is taken from memory location 2000H. This is indirect. In 8086, a far indirect jump can use a memory operand containing both IP and CS (depending on operand size), making it an intersegment indirect jump. ✅ Correct answer. 4. JMP [BX] Indirect jump through memory addressed by BX. Usually intrasegment (near indirect jump). ❌ Not in...

Constellation Diagrams of ASK, PSK, and FSK (with MATLAB Code + Simulator)

Constellation Diagrams: ASK, FSK, and PSK Comprehensive guide to signal space representation, including interactive simulators and MATLAB implementations. 📘 Overview 🧮 Simulator ⚖️ Theory Q-function 📚 Resources BASK (Binary ASK) Modulation Transmits one of two signals: 0 or $\sqrt{E_b}$, representing binary 0 and 1. BFSK (Binary FSK) Modulation Transmits one of two signals: $\sqrt{E_b}$ on the Y-axis or $\sqrt{E_b}$ on the X-axis. These are orthogonal signals. BPSK (Binary PSK) Modulation Transmits $+\sqrt{E_b}$ or $-\sqrt{E_b}$ (antipodal signaling). Signal Space Simulator Visualize Constellation Diagrams with Noise Control. SNR (dB): 15 ...

Which of the following statements are correct? A. If the intermediate frequency is too high, poor selectivity results even if sharp cutoff filters are used in the IF stage.

  61) Which of the following statements are correct?  A. If the intermediate frequency is too high, poor selectivity results even if sharp cutoff filters are used in the IF stage.  B. A high value of intermediate frequency increases tracking difficulties.  C. As the intermediate frequency is lowered, image frequency rejection becomes better.  D. A very low intermediate frequency can make the selectivity too sharp.  Choose the correct answer from the options given below:  1. A and B only [Option ID = 3073]  2. B and C only [Option ID = 3074]  3. C and D only [Option ID = 3075]  4. B and D only [Option ID = 3076 Answer: 4  Previous yr Question papers with Full Explanations → Electronics and Communiaction Study Materials → Try Interactive Online Simulator Run the Simulation The Superheterodyne Principle The...

MATLAB Code for ASK, FSK, and PSK (with Online Simulator)

MATLAB Code for ASK, FSK, and PSK Comprehensive implementation of digital modulation and demodulation techniques with simulation results. 📘 Theory 📡 ASK Code 📶 FSK Code 🎚️ PSK Code 🕹️ Simulator 📚 Further Reading Amplitude Shift Frequency Shift Phase Shift Live Simulator ASK, FSK & PSK HomePage MATLAB Code MATLAB Code for ASK Modulation and Demodulation COPY % The code is written by SalimWireless.Com clc; clear all; close all; % Parameters Tb = 1; fc = 10; N_bits = 10; Fs = 100 * fc; Ts = 1/Fs; samples_per_bit = Fs * Tb; rng(10); binar...