Skip to main content

Alamouti Scheme for 2x2 MIMO in MATLAB


 

 Read about the Alamouti Scheme first

MATLAB Code for Alamouti's Precoding Matrix for 2 X 2 MIMO

% Clear any existing data and figures
clc;
clear;
close all;

% Define system parameters
transmitAntennas = 2; % Number of antennas at the transmitter
receiveAntennas = 2; % Number of antennas at the receiver
symbolCount = 1000000; % Number of symbols to transmit
SNR_dB = 15; % Signal-to-Noise Ratio in decibels

% Generate random binary data for transmission
rng(10); % Set seed for reproducibility
transmitData = randi([0, 1], transmitAntennas, symbolCount);

% Perform Binary Phase Shift Keying (BPSK) modulation
modulatedSymbols = 1 - 2 * transmitData;

% Define Alamouti's Precoding Matrix
precodingMatrix = [1 1; -1i 1i];

% Encode and transmit data using Alamouti scheme
transmittedSymbols = zeros(transmitAntennas, symbolCount);
for idx = 1:2:symbolCount
transmittedSymbols(:, idx:idx+1) = precodingMatrix * modulatedSymbols(:, idx:idx+1);
end

% Simulate Rayleigh fading channel
channelMatrix = (randn(receiveAntennas, transmitAntennas) + 1i * randn(receiveAntennas, transmitAntennas)) / sqrt(2);

% Receive signal and add AWGN
receivedSignal = awgn(channelMatrix * transmittedSymbols, SNR_dB, 'measured');

% Decode and demodulate received symbols
decodedSymbols = zeros(transmitAntennas, symbolCount);
for idx = 1:2:symbolCount
% Estimate received symbols using channel information
receivedEstimation = channelMatrix' * receivedSignal(:, idx:idx+1);
% Decode symbols using Alamouti decoding
decodedSymbols(:, idx:idx+1) = precodingMatrix' * receivedEstimation;
end

% Perform BPSK demodulation to retrieve received binary data
receivedBinaryData = decodedSymbols < 0;

% Calculate error rate
errorCount = sum(sum(transmitData ~= receivedBinaryData));
errorRate = errorCount / (transmitAntennas * symbolCount);

% Display the error rate
disp(['Error rate: ', num2str(errorRate)]);

 

Output

 Error rate: 0

You can run a loop by varying the SNR values. You can plot the BER vs SNR graph easily.

 

Copy the MATLAB Code from Here

 

 

Alamouti Scheme Transmission Table

 

 

 

 

 

 

 

 

The above table illustrates how two orthogonal, time-diversity data streams are transmitted using two different time slots to improve the signal-to-noise ratio (SNR) at the receiver.

For a symbol stream S1,S2,S3,S4,…,Sn−1,SnS_1, S_2, S_3, S_4, \ldots, S_{n-1}, S_n, we first transmit S1S_1 and S2S_2 from antenna 1 and antenna 2, respectively. In the next time slot, we transmit −S2∗-S_2^* and S1∗S_1^* from antenna 1 and antenna 2, respectively.

Note: To enable the Alamouti scheme, at least two transmit antennas and one receive antenna are required.

In the third time slot, S3S_3 and S4S_4 are transmitted from antenna 1 and antenna 2. In the fourth time slot, −S4∗-S_4^* and S3∗S_3^* are transmitted from antenna 1 and antenna 2, respectively — and this pattern continues. [Read More ...]

 

Further Reading

  1.  Modified Alamouti's Scheme (STBC) in MATLAB (using QPSK)
  2. Alamouti's Scheme for MIMO Communication
  3. Theoretical Ber vs Snr for Alamouti Scheme 
  4. MATLAB Code for Multi-User STBC (using Alamouti's Scheme)
  5. Alamouti Scheme Simulator


Contact Us

Name

Email *

Message *

Popular Posts

GMSK BER vs SNR (with Simulation)

  GMSK Performance: Why the BER vs. SNR Curve Matters If you’ve ever wondered why GMSK (Gaussian Minimum Shift Keying) became the backbone of the global GSM revolution, the answer lies in its unique balance of spectral efficiency and power performance. But there is no free lunch in engineering. To get that sleek, narrow spectrum, you have to pay a price in Bit Error Rate (BER) . In this guide, we break down the theoretical BER vs. SNR performance of GMSK, the "magic" of the BT product, and how to optimize your link budget for real-world conditions. What is GMSK and Why Should You Care? GMSK is a derivative of MSK (Minimum Shift Keying) that uses a Gaussian pre-modulation filter. This filter "smooths" the phase transitions, significantly reducing sideband power. The result? A constant envelope signal that allows you to use high-efficiency Class-C amplifiers without distorting the signal. This is the secr...

UGC NET Electronic Science Previous Year Question Papers with Solutions

Download Papers and Solutions Exam Pattern Preparation Tips FAQs More Home / Engineering & Other Exams / UGC NET 2026 PYQ 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2026 - Question Paper Download PDF June 202...

OFDM Symbols and Subcarriers Explained

This article explains how OFDM (Orthogonal Frequency Division Multiplexing) symbols and subcarriers work. It covers modulation, mapping symbols to subcarriers, subcarrier frequency spacing, IFFT synthesis, cyclic prefix, and transmission. Step 1: Modulation First, modulate the input bitstream. For example, with 16-QAM , each group of 4 bits maps to one QAM symbol. Suppose we generate a sequence of QAM symbols: s0, s1, s2, s3, s4, s5, …, s63 Step 2: Mapping Symbols to Subcarriers Assume N sub = 8 subcarriers. Each OFDM symbol in the frequency domain contains 8 QAM symbols (one per subcarrier): Mapping (example) OFDM symbol 1 → s0, s1, s2, s3, s4, s5, s6, s7 OFDM symbol 2 → s8, s9, s10, s11, s12, s13, s14, s15 … OFDM sym...

What is a Supernode?

  Circuit Analysis What Is a Supernode? A supernode is formed when an ideal voltage source connects two non-reference nodes. It allows us to apply Kirchhoff's Current Law (KCL) to the combined circuit boundary. 1. Understanding a Supernode In nodal analysis, a voltage source between two unknown-voltage nodes makes the current through that source difficult to express directly using Ohm's law. We combine the two nodes and the voltage source into one extended region called a supernode. Key idea Apply KCL around the outer boundary of the supernode, then use the voltage source to write an additional voltage equation. 2. Supernode Circuit Diagram The voltage source connects nodes V L an...

The cutoff frequency (in GHz) for the dominant TE10 mode of an air-filled rectangular waveguide of ...

  Q. The cutoff frequency (in GHz) for the dominant TE10 mode of an air-filled rectangular waveguide of inner dimension 0.28 inch×0.14 inch is __. (rounded off to two decimal places). Given Information Waveguide dimensions = 0.28 inch × 0.14 inch Wider dimension (a) = 0.28 inch Smaller dimension (b) = 0.14 inch Medium = Air Dominant mode = TE 10 Speed of light (c) = 3 × 10 8 m/s Step 1: Cutoff Frequency Formula The cutoff frequency of a rectangular waveguide is: f c = (c / 2) √[(m/a) 2 + (n/b) 2 ] For the dominant TE 10 mode: m = 1, n = 0 f c = c / 2a Step 2: Convert Inch into Meter We know that 1 inch = 0.0254 meter. a = 0.28 × 0.0254 a = 0.007112 m ...

SRAM, DRAM, EPROM, MRAM, and DDRAM Explained

Computer Fundamentals Types of Memory and Their Technologies Understand the fundamental relationship between different types of computer memory and the technologies used to implement them. Fundamental Matching Memory type, technology, and key characteristics Memory Type Technology Key Characteristic Cache Memory SRAM Very fast; stores frequently accessed data Main Memory DRAM Holds programs and data currently in use Au...

A binary ripple counter is designed to count (0)₁₀ to (64)₁₀. Which of the following is/are the number of flip-flops required ...

  Q. A binary ripple counter is designed to count  (0)₁₀ to (64)₁₀ . Which of the following is/are the number of flip-flops required to design the counter?   (A) 6 (B) 7 (C) 4 (D) 5 Solution A binary ripple counter must count from (0)₁₀ to (64)₁₀ , including both endpoints. Step 1: Calculate the total number of states Since both 0 and 64 are included, add 1 to the difference: N = Last value − First value + 1 N = 64 − 0 + 1 = 65 states The counter visits every integer from 0 through 64: 0, 1, 2, 3, ..., 63, 64 There are 65 distinct states in total. Step 2: Calculate the number of flip-flops Each flip-flop stores one bit. With n flip-flops, the counter can represent 2ⁿ distinct states. 2⁶ = 64 states (not enough) 2⁷ = 128 states (eno...