For SSS, the following all must be time-invariant:
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Mean
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Variance
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Autocorrelation
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All higher-order moments
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All joint PDFs
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All marginal PDFs
Everything.
That’s why SSS is a very strong condition.
A random process is strict-sense stationary if for every:
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Positive integer
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Any set of time instants
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Any time shift
the joint distribution satisfies:
A Large Strictly Stationary Example
Let’s define a random process where:
X(t) = 0 with probability 1/2 X(t) = 1 with probability 1/2
Each time point is independent. This is like an infinite sequence of fair coin flips.
t: 1 2 3 4 5 6 7 8 9 10 ... X(t): 1 0 1 1 0 0 1 0 1 1 ...
Joint Probability of Many Values
Pick 5 time points: X(10), X(11), X(12), X(13), X(14)
We want:
P(X(10)=1, X(11)=0, X(12)=1, X(13)=1, X(14)=0)
Because each is independent with probability 1/2:
P = (1/2) × (1/2) × (1/2) × (1/2) × (1/2) = 1/32
Shift by Any Amount h
Shift by h = 20. Now consider:
X(30), X(31), X(32), X(33), X(34)
We want the same pattern:
P(X(30)=1, X(31)=0, X(32)=1, X(33)=1, X(34)=0) = 1/32
The joint probability did not change after shifting. This is strict stationarity.
Large Example: 100 Time Points
The probability of ANY specific pattern of 100 values is:
P = (1/2)^100
After shifting time by any h:
P = (1/2)^100
Again, the joint probability stays the same → strict stationarity.
Is Joint Probability Just Multiplication?
Yes — ONLY when the variables are independent
P(A ∩ B ∩ C) = P(A) × P(B) × P(C)
In our fair-coin process:
P(X(t1)=x1, ..., X(tn)=xn) = Î P(X(ti)=xi)
No — if variables are dependent
Example: if X(t+1) = X(t) always, then:
P(X(1)=0, X(2)=0) = P(X(1)=0)
You cannot multiply because the variables are not independent.
Final Summary
- Independence → joint probability = multiplication of each probability
- Dependence → cannot multiply
- In the fair-coin process:
- each time has same distribution
- all times independent
- shifting does not change joint probability
- → strictly stationary
Further Reading
- Wide Sense Stationary Signal