The bridge rectifier circuit has: Vi = 30 V, RL = 300Ω, diode drop VF = 0.7 V. Find peak output voltage and peak output current.
- A. 30 V, 100 mA
- B. 42.42 V, 141.4 mA
- C. 41 V, 137 mA
- D. 28.6 V, 95.33 mA
Answer
Step 1: Peak Input Voltage
Vpeak = 30 × √2 = 42.42 V
Step 2: Diode Drop
Drop = 2 × 0.7 = 1.4 V
Step 3: Output Voltage
Vo = 42.42 − 1.4 = 41 V
Step 4: Output Current
Io = 41 / 300 = 0.137 A = 137 mA
Correct Option: C
