Skip to main content

5G: Spectral Bands, Speed, and Other Factors



Lower carrier frequencies (< 6 GHz) are unable reliable signal propagation for 5G. However, only limited spectral bands are available in the sub-6 GHz spectrum. Only those frequencies are inadequate to meet the relentless increase in data rates in 5G wireless networks. So, what is the solution here? Exploration of the unused, high-frequency mm-wave band could be a good choice, ranging from 6 to 300 GHz. 
Mm-wave standards are already defined for indoor wireless personal area networks (WPAN) - IEEE 802.15.3c and wireless local area networks (WLAN) - IEEE 802.11.ad.


Which countries have 5G now, and what frequency bands are they using?

5G is now available in many countries. China and the United States are at the top of the list. Brand new 5G technology benefits approximately 356 cities in China and approximately 296 cities in the United States. Other countries that have already implemented 5G include the Philippines, South Korea, Canada, Spain, Italy, Germany, the United Kingdom, Saudi Arabia, and others.

In general, 5G currently employs three types of frequency bands. The first is frequency of less than 6 GHz or Sub-6 GHz band. Other frequency bands are in the millimeter wave range. It will also use low 5G bands, such as 600 MHz00 MHz, to improve coverage, particularly in rural areas.

For 5G communication, China, for example, uses frequencies ranging from 600 MHz to 4700 MHz. The frequencies in the United States range from 600 MHz to 4200 MHz. These bands are intended for end-user use. You may have heard that telecom companies also purchase high remedy frequency (i.e., millimeter wave) spectrum for 5G deployment. However, those extremely high frequencies are appropriate for 5G backhaul connections.

The current 5G frequency bands can be classified into three categories.

The Low Band (Usually ranges from 600 to 900 MHz, and they are suitable for rural deployment of 5G where signals need to traverse long distances from cell towers)
The Middle Band (Frequency ranges from 1 to 7 GHz)
The High Band (These are millimeter wave bands. They range from 24 to 48 GHz)


Current Speed of 5G:

The average 5G speed is 100 Mbps, which means that 5G users will receive 100 megabits per second. Depending on the coverage, number of users available per channel (5G communication channel), and other factors, the pick data throughput rate can range from 1 Gbps to 10 Gbps.

Recently, it was claimed that a 5G network could achieve 5 Gbps throughput using a 28 GHz band and 800 MHz bandwidth with carrier aggregation.


Millimeter wave applications in 5G:

We know that companies own millimeter wave spectrums in 5G auctions. In fact, we want to use such extremely high-frequency bands for ultra-high data rates and ultra-low latency in 5G deployment. These are critical for any network to lead automation in various sectors such as industry (machine-to-machine communication, for example), telemedicine, augmented reality (AR), virtual reality (VR), and so on.

However, those mm-wave bands are appropriate for backhaul connections in which two high 5G towers communicate via LOan S (line of sight) path and deliver very high data rates from large cell towers to nearby small cell towers or access points (APs). End users can connect to the internet via a nearby cell tower.


Also, Read About
[1] 5G Theoretical Aspects | Frequency and Spectrum, Speed, Massive MIMO & OFDM
# News about 5G

Contact Us

Name

Email *

Message *

Popular Posts

UGC NET Electronic Science Previous Year Question Papers with Solutions

Home / Engineering & Other Exams / UGC NET 2026 PYQ ⬇️ Download Papers and Solutions 📋 Exam Pattern 💡 Preparation Tips ❓ FAQs 📊 Exam Highlights: Electronic Science (88) Feature Details Junior Research Fellowship (JRF) ₹37,000 + HRA per month Eligibility M.Sc/M.Tech in Electronics (55%) Validity of Certificate JRF (3 Years) | Lectureship (Lifetime) 📥 Download UGC NET Electronics PDFs Complete collection of previous year question papers, answer keys and explanations for Subject Code 88. Start Downloading 📂 View All Question Papers June 2025 - Question Paper Download PDF June 2025 - Solved Paper + Explanation ...

BER vs SNR for M-ary QAM, M-ary PSK, QPSK, BPSK, ...(MATLAB Code + Simulator)

Bit Error Rate (BER) & SNR Guide Analyze communication system performance with our interactive simulators and MATLAB tools. 📘 Theory 🧮 Simulators 💻 MATLAB Code 📚 Resources BER Definition SNR Formula BER Calculator MATLAB Comparison 📂 Explore M-ary QAM, PSK, and QPSK Topics ▼ 🧮 Constellation Simulator: M-ary QAM 🧮 Constellation Simulator: M-ary PSK 🧮 BER calculation for ASK, FSK, and PSK 🧮 Approaches to BER vs SNR What is Bit Error Rate (BER)? The BER indicates how many corrupted bits are received compared to the total number of bits sent. It is the primary figure of merit f...

Q-function in BER vs SNR Calculation

Q-function in BER vs. SNR Calculation | Interactive Guide Q-function in BER vs. SNR Calculation In digital communications and signal processing, the Q-function plays a significant role in predicting system reliability. It allows engineers to quantify the probability that Gaussian noise will exceed a specific threshold, causing a bit error. What is the Q-function? The Q-function is a mathematical function representing the tail probability of the standard normal (Gaussian) distribution. It is the complementary cumulative distribution function (CCDF) of a standard Gaussian distribution. Q(x) = (1 / √(2Ï€)) ∫â‚“∞ e^(-t² / 2) dt Q-Function Interactive Simulator Move the slider to see how the "Tail Probability" (the area in red) changes. This area represents the Probability of Error (BER) . Threshold Distance ( x ) — (Simulates Increasing SNR) ...

MATLAB Code for ASK, FSK, and PSK (with Online Simulator)

MATLAB Code for ASK, FSK, and PSK Comprehensive implementation of digital modulation and demodulation techniques with simulation results. 📘 Theory 📡 ASK Code 📶 FSK Code 🎚️ PSK Code 🕹️ Simulator 📚 Further Reading Amplitude Shift Frequency Shift Phase Shift Live Simulator ASK, FSK & PSK HomePage MATLAB Code MATLAB Code for ASK Modulation and Demodulation COPY % The code is written by SalimWireless.Com clc; clear all; close all; % Parameters Tb = 1; fc = 10; N_bits = 10; Fs = 100 * fc; Ts = 1/Fs; samples_per_bit = Fs * Tb; rng(10); binar...

Online Simulator for ASK, FSK, and PSK

Interactive Digital Signal Processing (DSP) Tutorial and Simulator for ASK, FSK, and BPSK modulation techniques. Try our new Digital Signal Processing Simulator!   •   Interactive ASK, FSK, and BPSK tools updated for 2025. Start Now Digital Modulation Visualizer: ASK, FSK, & BPSK Simulator Learn and visualize binary modulation techniques (ASK, FSK, BPSK) in real-time with adjustable carrier and sampling parameters. Perfect for DSP students and engineers. 📡 ASK Simulator 📶 FSK Simulator 🎚️ BPSK Simulator 📚 More Topics ASK Modulator FSK Modulator BPSK Modulator More Topics 1. ASK (Amplitude Shift Keying) Simulat...

UGC NET Electronic Science June 2025 Question Paper with Answer Key & Detailed Solutions

Home / UGC NET PYQ / June 2025 Solved UGC NET Electronic Science June 2025 Question Paper with Answer Key and Full Explanations 📥 Download Question Paper (PDF) 2025 2024 2023 2022 2021 2020 Explanations 1.  Answer: Option (3) For forming a p-type semiconductor, the dopant must be a trivalent impurity (three valence electrons) so that it creates acceptor levels and holes become the majority carriers. Among the given elements, boron (B) is a group-III element (trivalent). Arsenic (As) and phosphorus (P) are group-V (pentavalent) donors that produce n-type material, and germanium (Ge) is a group-IV element usually used as the semiconductor, not as an acceptor dopant. Hence, doping an intrinsic semiconductor with B produces a p-type semiconductor. 2.  Answer: Option (4) The ohmic resistance of a JFET at zero gate bias is given by the standard relation: R DS(on) = V P / I DSS ...

Which of the following statements are correct? A. If the intermediate frequency is too high, poor selectivity results even if sharp cutoff filters are used in the IF stage.

  61) Which of the following statements are correct?  A. If the intermediate frequency is too high, poor selectivity results even if sharp cutoff filters are used in the IF stage.  B. A high value of intermediate frequency increases tracking difficulties.  C. As the intermediate frequency is lowered, image frequency rejection becomes better.  D. A very low intermediate frequency can make the selectivity too sharp.  Choose the correct answer from the options given below:  1. A and B only [Option ID = 3073]  2. B and C only [Option ID = 3074]  3. C and D only [Option ID = 3075]  4. B and D only [Option ID = 3076 Answer: 4  Previous yr Question papers with Full Explanations → Electronics and Communiaction Study Materials → Try Interactive Online Simulator Run the Simulation The Superheterodyne Principle The...

Shannon Limit Explained: Negative SNR, Eb/No and Channel Capacity

Understanding Negative SNR and the Shannon Limit An explanation of Signal-to-Noise Ratio (SNR), its behavior in decibels, and how Shannon's theorem defines the ultimate communication limit. Signal-to-Noise Ratio in Shannon’s Equation In Shannon's equation, the Signal-to-Noise Ratio (SNR) is defined as the signal power divided by the noise power: SNR = S / N Since both signal power and noise power are physical quantities, neither can be negative. Therefore, the SNR itself is always a positive number. However, engineers often express SNR in decibels: SNR(dB) When SNR = 1, the logarithmic value becomes: SNR(dB) = 0 When the noise power exceeds the signal power (SNR < 1), the decibel representation becomes negative. Behavior of Shannon's Capacity Equation Shannon’s channel capacity formula is: C = B log₂(1 + SNR) For SNR = 0: log₂(1 + SNR) = 0 When SNR becomes smaller (including negative values in dB), the expression approache...